Replace Employee ID With The Unique Identifier
LeetCode 1509 | Difficulty: Easyβ
EasyProblem Descriptionβ
Table: Employees
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| id | int |
| name | varchar |
+---------------+---------+
id is the primary key (column with unique values) for this table.
Each row of this table contains the id and the name of an employee in a company.
Table: EmployeeUNI
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| id | int |
| unique_id | int |
+---------------+---------+
(id, unique_id) is the primary key (combination of columns with unique values) for this table.
Each row of this table contains the id and the corresponding unique id of an employee in the company.
Write a solution to show the unique ID of each user, If a user does not have a unique ID replace just show null.
Return the result table in any order.
The result format is in the following example.
Example 1:
Input:
Employees table:
+----+----------+
| id | name |
+----+----------+
| 1 | Alice |
| 7 | Bob |
| 11 | Meir |
| 90 | Winston |
| 3 | Jonathan |
+----+----------+
EmployeeUNI table:
+----+-----------+
| id | unique_id |
+----+-----------+
| 3 | 1 |
| 11 | 2 |
| 90 | 3 |
+----+-----------+
Output:
+-----------+----------+
| unique_id | name |
+-----------+----------+
| null | Alice |
| null | Bob |
| 2 | Meir |
| 3 | Winston |
| 1 | Jonathan |
+-----------+----------+
Explanation:
Alice and Bob do not have a unique ID, We will show null instead.
The unique ID of Meir is 2.
The unique ID of Winston is 3.
The unique ID of Jonathan is 1.
Topics: Database
Approachβ
Direct Approachβ
This problem can typically be solved with straightforward iteration or simple data structure usage. Focus on correctness first, then optimize.
When to use
Basic problems that test fundamental programming skills.
Solutionsβ
Solution 1: MS SQL (Best: 2989 ms)β
| Metric | Value |
|---|---|
| Runtime | 2989 ms |
| Memory | 0B |
| Date | 2020-03-12 |
Solution
/* Write your T-SQL query statement below */
select unique_id, name from Employees E
LEFT OUTER JOIN EmployeeUNI EU
ON E.id = EU.id
Complexity Analysisβ
| Approach | Time | Space |
|---|---|---|
| Solution | $O(n)$ | $O(1) to O(n)$ |
Interview Tipsβ
Key Points
- Start by clarifying edge cases: empty input, single element, all duplicates.