Construct Binary Tree from Preorder and Inorder Traversal
LeetCode 105 | Difficulty: Mediumβ
MediumProblem Descriptionβ
Given two integer arrays preorder and inorder where preorder is the preorder traversal of a binary tree and inorder is the inorder traversal of the same tree, construct and return the binary tree.
Example 1:

Input: preorder = [3,9,20,15,7], inorder = [9,3,15,20,7]
Output: [3,9,20,null,null,15,7]
Example 2:
Input: preorder = [-1], inorder = [-1]
Output: [-1]
Constraints:
- `1 <= preorder.length <= 3000`
- `inorder.length == preorder.length`
- `-3000 <= preorder[i], inorder[i] <= 3000`
- `preorder` and `inorder` consist of **unique** values.
- Each value of `inorder` also appears in `preorder`.
- `preorder` is **guaranteed** to be the preorder traversal of the tree.
- `inorder` is **guaranteed** to be the inorder traversal of the tree.
Topics: Array, Hash Table, Divide and Conquer, Tree, Binary Tree
Approachβ
Hash Mapβ
Use a hash map for O(1) average lookups. Store seen values, frequencies, or indices. The key question: what should I store as key, and what as value?
When to use
Need fast lookups, counting frequencies, finding complements/pairs.
Solutionsβ
Complexity Analysisβ
| Approach | Time | Space |
|---|---|---|
| Hash Map | $O(n)$ | $O(n)$ |
Interview Tipsβ
Key Points
- Discuss the brute force approach first, then optimize. Explain your thought process.
- Consider: "What information do I need from each subtree?" β this defines your recursive return value.
- Hash map gives O(1) lookup β think about what to use as key vs value.